METODE BAGI DUA [TUGAS METNUM] C++

• C++

#include 
#include 
#include 

float a,c,b,F_a,F_c,F_b,E;
int max;

float f(float x)
{
   return (x*x*x*x*x)-x-1;
}

void main()
{
   int it;
   char selang;
   float epsilon;

   printf("Batas bawah      = "); scanf("%f",&a);
   printf("Batas atas       = "); scanf("%f",&b);
   printf("Toleransi Error  = "); scanf("%f",&E);
   printf("Iterasi maksimum = "); scanf("%d",&max);

   it = 0;
   F_a = f(a);
   F_b = f(b);
   if(F_a * F_b > 0) printf("Nilai F(a) x F(b) > 0\n");
   else
   {
    printf("--------------------------------------------------------------------------\n");
      printf(" r     a       b        c       f(a)      f(b)     f(c)  selang  lebarnya \n");
      printf("--------------------------------------------------------------------------\n");
      do
      {
      it = it + 1;
         c = (a + b) / 2;
         F_c = f(c);
         if(F_a * F_c <= 0) { selang ='A'; }
         else {selang ='B'; }

         printf("%2d %8.5f %8.5f %8.5f %8.5f %8.5f %8.5f   C%c    %8.5f \n",
                 it,a,b,c,F_a,F_b,F_c,selang,fabs(a-c));
         epsilon = fabs(a-c);
         if(F_a * F_c <= 0) { b = c; F_b = F_c; }
         else { a = c; F_a = F_c; }
      } while(it <= max && epsilon > E);

      if(it <= max)
      {
         printf("\n Hampiran (pendekatan) nilai x = %g\n",c);
         printf(" pada iterasi ke-%d",it);
      }
      else printf("Toleransi tidak terpenuhi, Jumlah Iterasi kurang\n");
   }
   getch();
}

• HASIL

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